Question

Me ajudem por favor !!!!!

Answer 1

Vamos lá...

1-

$a)90 + 35 + x = 180 \\ x = 180 - 90 - 35 \\ x = 55$
$b)60 + 70 + x = 180 \\ x = 180 - 60 - 70 \\ x = 50$
$c)30 + 90 + x = 180 \\ x = 180 - 90 - 30 \\ x = 60$

2- Escaleno, equilátero e isosceles, respectivamente.


3- arestas: 6
vértices: 6


4- obtusângulo


5- 90°


6-

$a) \frac{10}{x} = \frac{20}{14} \\ 20x = 140 \\ x = \frac{140}{20} = 7$
$b) \frac{8}{20} = \frac{x}{5} \\ 20x = 40 \\ x = \frac{40}{20} = 2$


Bons estudos :p

Answer 2

\begin{lgathered}a)90 + 35 + x = 180 \\ x = 180 - 90 - 35 \\ x = 55\end{lgathered}a)90+35+x=180x=180−90−35x=55​ 
\begin{lgathered}b)60 + 70 + x = 180 \\ x = 180 - 60 - 70 \\ x = 50\end{lgathered}b)60+70+x=180x=180−60−70x=50​ 
\begin{lgathered}c)30 + 90 + x = 180 \\ x = 180 - 90 - 30 \\ x = 60\end{lgathered}c)30+90+x=180x=180−90−30x=60​ 

2- Escaleno, equilátero e isosceles, respectivamente.


3- arestas: 6
vértices: 6


4- obtusângulo


5- 90°


6- 

\begin{lgathered}a) \frac{10}{x} = \frac{20}{14} \\ 20x = 140 \\ x = \frac{140}{20} = 7\end{lgathered}a)x10​=1420​20x=140x=20140​=7​ 
\begin{lgathered}b) \frac{8}{20} = \frac{x}{5} \\ 20x = 40 \\ x = \frac{40}{20} = 2\end{lgathered}b)208​=5x​20x=40x=2040​=2​