Question

Me ajudem por favor

1) Converta as escalas:


a)20°C em K

b)400K em °C

c)50°C em °F

d)132°F em °C

e)173K em °F

f)0°F em K

Answer 1

Resposta:

$tk=tc+273\\\\tc=tk-273\\\dfrac{c}{5}=\dfrac{f-32}{9}\\\\a)tk=20+273\\\boxed{tk=293^{o}K}\\\\b)tc=400-273\\\boxed{tc=127^{o}C}\\\\c)^{o}F=(1,8*C)+32\\^{o}F=(1,8*50)+32\\^{o}F=90+32\\\boxed{F=122^{o}F}\\\\d)^{o}C=\dfrac{^{o}F-32}{1,8}\\^{o}C=\dfrac{132-32}{1,8}\\^{o}C=\dfrac{100}{1,8}\\\boxed{^{o}C=55,55...^{o}C}\\\\e)\dfrac{k-273}{5}=\dfrac{F-32}{9}\\\dfrac{173-273}{5}=\dfrac{F-32}{9}\\(-100)*9=5F-160\\5F=160-900\\5F=-740\\F=\dfrac{-740}{5}\\\boxed{F=-128^{o}F}$

$f)\dfrac{k-273}{5}=\dfrac{F-32}{9}\\\dfrac{k-273}{5}=\dfrac{0-32}{9}\\9K-2457=5*(-32)\\9K=2457-160\\9K=2297\\K=\dfrac{2297}{9}\\\boxed{K=255,222...^{o}K}$

Explicação: