Question

ME AJUDEM PLS COM CÁLCULOS!!!!!!! 1) $\frac{ (2^4)^8}{(4^8)^2}$

Answer 1

Oie, Td Bom?!

$= \frac{(2 {}^{4}) {}^{8} }{(4 {}^{8} ) {}^{2} }$

$= \frac{2 {}^{4 \: . \: 8} }{4 {}^{8 \: . \: 2} }$

$= \frac{2 {}^{32} }{4 {}^{16} }$

$= \frac{2 {}^{32} }{2 {}^{32} }$

$= 1$

Att. Makaveli1996