Question

Me ajudem, please: -(-2)^4 + (-2)^5 × 4^-3

Answer 1

$-(-2)^4+(-2)^5\cdot4^{-3}$

$-16-32\cdot(\frac{1}{4})^3$

$-48\cdot\frac{1}{64}$

$-\frac{48}{64}$

$-\frac{3}{4}$