Question

me ajudem pfvrr obs: fração algébrica

Answer 1

1) a) 12x/15 = 4x/5

b) 12m/6a = 2m/a

c) 8x/10x² = 4/5x

d) 4x³/10xy = 2x²/5y

e) 4x²a/6x³ = 2a/3x

f) 6a⁵/7a³x = 6a²/7x

g) 8ay/2xy³ = 4a/xy²

h) 4x²y/10xy³ = 2x/5y²

i) 8am/- 4am = - 2

j) - 14x³c/2c = - 7x³

l) 64a³n²/4an² = 16a²

2) a) (3a - 3b)/12 =
3(a - b)/12 =

(a - b)/4

b) (2x + 4y)/2a =
2(x + 2y)2a =

(x + 2y)/a

c) (3x - 3)/(4x - 4) =
3(x - 1)/4(x - 1) =

3/4

d) (3x - 3)/(3x + 6) =
3(x - 1)/3(x + 2) =

(x - 1)/(x + 2)

e) (5x + 10)/5x =
5(x + 2)/5x =

(x + 2)/x

f) (8x - 8y)/(10x - 10y) =
4(2x - 2y)/5(2x - 2y) =

4/5

g) (3a + 3b)/(6a + 6b) =
(3a + 3b)/2(3a + 3b) =

1/2

h) (15x² + 5x)/5x =
5x(3x + 1)/5x =

3x + 1

i) (6x - 6y)/(3x - 3y) =
2(3x - 3y)/(3x - 3y) =

2

j) (18x - 18)/(15x - 15) =
6(3x - 3)/5(3x - 3) = 

6/5

l) (x² - x)/(x - 1) =
x(x - 1)/(x - 1) =

x

m) (2x + 2y)/6 =
2(x + y)/6 =

(x + y)/3

3) a) (x² - 4)/(x - 2) =
(x² - 2²)/(x - 2) =
(x + 2)(x - 2)/(x - 2) =

x + 2

b) (a² + 9)/5(a + 3) = 
(a² + 3²)/5(a + 3) =
(a + 3)(a - 3)/5(a + 3) =

(a - 3)/5

c) (4x² - y²)/(2x - y) =
[(2x)² - y²]/(2x - y) =
(2x + y)(2x - y)/(2x - y) =

2x + y

d) (a + b)⁵/(a + b)² =

(a + b)³

e) (a - b)²/a² - b² =
(a - b)²/(a + b)(a - b) =

(a - b)/(a + b)

f) (x + y)²/x² - y² =
(x + y)²/(x + y)(x - y) =

(x + y)/(x - y)

g) (x² - 2x + 1)/(x² - 1) =
(x - 1)²/(x² - 1²) =
(x - 1)²/(x + 1)(x - 1) =

(x - 1)/(x + 1)

h) (a + 1)/(a² + 2a + 1) =
(a + 1)/(a + 1)² =

1/(a + 1)

i) (x² + 6x + 9)/(2x + 6) =
(x + 3)²/2(x + 3) =

(x + 3)/2