Question

Me ajudem pfvr:/
Tenho que entregar amanhã

Answer 1

Resposta:

Explicação passo a passo:

$Regras...$

$a^{m}\:.\:a^{n}=a^{(m+n)}$

$a^{m}\::\:a^{n}=a^{(m-n)}$

$(a^{m})^{n} =a^{m\:.\:n}$

$[(-\frac{1}{2}) ^{2}] ^{-3} =(-\frac{1}{2}) ^{-6}$

$(-\frac{1}{2})\:.\: (-\frac{1}{2})^{5} \:.\:(-\frac{1}{2})^{-3} =(-\frac{1}{2})^{(1+5-3)} =(-\frac{1}{2})^{3}$

$Portanto...$

$(-\frac{1}{2}) ^{-6}:(-\frac{1}{2}) ^{3}=$

$(-\frac{1}{2}) ^{(-6-3)}=$

$(-\frac{1}{2}) ^{-9}$

$Resposta\:Final=>(-\frac{1}{2}) ^{-9}$