Question

me ajudem pfvr , ta na foto a pergunta

Answer 1

g)
$\frac{2 m^{2} }{3} - \frac{m}{2} +1- \frac{m^{2} }{2} + \frac{2m}{3} -1=$

mmc de tudo

$\frac{4 m^{2}-3m+6-3 m^{2} +4m-6 }{6} =$

$\frac{ m^{2} }{6}$+$\frac{m}{6}$

h)
$\frac{m}{2} - \frac{mn}{3} +2+mn+1- \frac{m}{2} =$

mmc de tudo

$\frac{3m-2mn+12+6mn+6-3m}{6} =$

$\frac{4mn}{6} + \frac{18}{6} =$

$\frac{2mn}{3} +3$


i)
$2a b^{2} - \frac{ a^{2}b }{3} - \frac{3a b^{2} }{4} + a^{2} b=$

mmc de tudo

$\frac{24a b^{2}-4 a^{2}b-9a b^{2} +12 a^{2} b }{12} =$

$\frac{15a b^{2} }{12} + \frac{8 a^{2}b }{12} =$

$\frac{5a b^{2} }{4} + \frac{2 a^{2}b }{3}$