Question

Me ajudem pfvr :<
$\sqrt{81} \div ( {4}^{2} - {5}^{2} ) =$
$\sqrt{3600} \div \sqrt{25} =$
$4 \times {( - 5)}^{3} + {( - 20)}^{2} =$

$7 \times {( - 2)}^{2} - 5 \times {( - 2)}^{3} - {10}^{2} =$
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Answer 1

Resposta:

$\sqrt{81} \div (4^{2}-5^{2} )=-9$

$\sqrt{3600} \div\sqrt{25}=12$

$4\times(-5)^{3} +(-20)^{2}=-2100$

$7\times(-2)^2-4\times(-2)^3-10^2=-40$

Explicação passo a passo:

$\sqrt{81} \div (4^{2}-5^{2} )\\9\div(16-25)\\9\div(-9)\\-9$

$\sqrt{3600} \div\sqrt{25}\\60\div5\\ 12$

$4\times(-5)^{3} +(-20)^{2}\\4\times (-625)+400\\-2500+400\\-2100$

$7\times(-2)^2-4\times(-2)^3-10^2\\7\times4-4\times(-8)-100\\28+32-100\\60-100\\-40$