Question

me ajudem pfvr
complete
sen 135°=
cos 90°=
sen 180°=
sen 120°=
sen 300°=
cos 210°=
​

Answer 1

$\mathsf{sen(135^{\circ})=sen(45^{\circ})=\dfrac{\sqrt{2}}{2}}$

$\mathsf{cos(90°)=0}$

$\mathsf{sen(180^{\circ})=0}$

$\mathsf{sen(120^{\circ})=sen(60^{\circ})=\dfrac{\sqrt{3}}{2}}$

$\mathsf{sen(300^{\circ})=-sen(60^{\circ})=-\dfrac{\sqrt{3}}{2}}$

$\mathsf{cos(210^{\circ})=-cos(30^{\circ})=-\dfrac{\sqrt{3}}{2}}$