Question

me ajudem pfvr.......​

Answer 1

Explicação passo-a-passo:

01)

a)

$f(x) = {x}^{2} - 5x + 6$

$0 = {x}^{2} - 5x + 6$

${x}^{2} - 5x + 6 = 0$

${x}^{2} - 2x - 3x + 6 = 0$

$x \times (x - 2) - 3(x - 2) = 0$

$(x - 2) \times(x - 3) = 0$

$x - 2 = 0 \\ x - 3 = 0$

$x = 2 \\ x = 3$

$2 + 3$

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b)

$f(x) = {2x}^{2} - 2x - 24$

$0 = {2x}^{2} - 2x - 24$

${2x}^{2} - 2x - 24 = 0$

${x}^{2} - x - 12 = 0$

${x}^{2} + 3x - 4x - 12 = 0$

$x \times (x + 3) - 4(x + 3) = 0$

$(x + 3) \times (x - 4) = 0$

$x + 3 = 0 \\ x - 4 = 0$

$x = - 3 \\ x = 4$

$- 3 + 4$

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ATT:ARMANDO