Question

Me ajudem pfvr!!!!!!!

Answer 1

a) log$log_{ \sqrt[5]{2} }$ 32 = x => $(\sqrt[5]{2})^{x}  = 32$ => $(2^{ \frac{1}{5} })^{x} =2^{5}=> \frac{x}{5}=5=>x=25$

b) $log_{ \sqrt[5]{8} } \sqrt[11]{256}=x=> (\sqrt[5]{8})^{x}=\sqrt[11]{256}=>( \sqrt[5]{2^{3} })^{x}= \sqrt[11]{2^{8} }=>(2^{ \frac{3}{5} })^{x}= 2^{ \frac{8}{11} }=> \frac{3}{5}x= \frac{8}{11}=>x= \frac{ \frac{8}{11} }{ \frac{3}{5} }=>x= \frac{8}{11}. \frac{8}{3}=>x= \frac{64}{33}$

c) $log_{ \sqrt[7]{ \frac{5}{7} } } \frac{49}{625}=x=> (\sqrt[7]{ \frac{5}{7} })^{x}= (\frac{7}{25}) ^{2}=>[(  \frac{5}{7})^{ \frac{1}{7} }]^{x}=( \frac{7}{25})^{2}=>(\frac{5}{7})^{ \frac{x}{7} }=( \frac{25}{7})^{-2}$