Question

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Answer 1

98g de ácido sulfúrico ------------ 342g de sulfato de alumínio

xg de ácido sulfúrico ------------ 1002g de sulfato de alumínio.

1002*98/342= 287,12g

Aproximadamente 287g.

Answer 2

Explicação:

$\sf H_{2}SO_{4}+Al(OH)_3~\Rightarrow~Al_{2}(SO_{4})_{3}+H_{2}O$

Balanceando:

$\sf 3H_{2}SO_{4}+2Al(OH)_3~\Rightarrow~Al_{2}(SO_{4})_{3}+6H_{2}O$

• $\sf MM(H_{2}SO_{4})=2\cdot1+32+4\cdot16$

$\sf MM(H_{2}SO_{4})=2+32+64$

$\sf MM(H_{2}SO_{4})=98~g/mol$

• $\sf Al_{2}(SO_{4})_3=2\cdot27+3\cdot32+12\cdot16$

$\sf Al_{2}(SO_{4})_3=54+96+192$

$\sf Al_{2}(SO_{4})_3=342~g/mol$

Temos:

$\sf 3H_{2}SO_{4}+2Al(OH)_3~\Rightarrow~Al_{2}(SO_{4})_{3}+6H_{2}O$

$\sf ~~3\cdot98~~~~~~~~~~~~~~~\Rightarrow~~~~~~~~~~~~~~~~342$

$\sf ~~~~~x~~~~~~~~~~~~~~~~~~~\Rightarrow~~~~~~~~~~~~~~1002$

$\sf \dfrac{3\cdot98}{x}=\dfrac{342}{1002}$

$\sf \dfrac{294}{x}=\dfrac{342}{1002}$

$\sf 342x=294\cdot1002$

$\sf 342x=294588$

$\sf x=\dfrac{294588}{342}$

$\sf x=861,37~g$