Question

Me ajudem pfv.......(Questão 2)

Answer 1

A)
$\sqrt{0.36} = \sqrt{ \frac{36}{100} } = \sqrt{ \frac{ {6}^{2} }{ {10}^{2} } } = \frac{6}{10} = \frac{3}{5}$

B)
$\sqrt{0.0049} = \sqrt{ \frac{49}{1000} } = \sqrt{ \frac{ {7}^{2} }{ {10}^{4} } } = \frac{7}{ {10}^{2} } = \frac{7}{100}$

C)
$\sqrt{0.000009} = \sqrt{ \frac{9}{1000000} } = \sqrt{ \frac{ {3}^{2} }{ {10}^{6} } } = \frac{3}{10000}$

D)
$\sqrt{0.0400} = \sqrt{ \frac{4}{100} } = \sqrt{ \frac{ {2}^{2} }{ {10}^{2} } } = \frac{2}{10} = \frac{1}{5}$

E)
$\sqrt{1.96} = \sqrt{ \frac{196}{100} } = \sqrt{ \frac{ {13}^{2} }{ {10}^{2} } } = \frac{13}{10}$

Espero ter ajudado! :)