me ajudem pfv, preciso pra amanhã :)
Soluções para a tarefa
Boa noite, Karol!
Bom, vamos lá... Temos que usar a formula de Bháskara.
A)x²-4x+3=0 B)x²+x-20=0 C)-15x²-2x+13=0
a=1 a=1 a= -15
b= -4 b=1 b= -2
c=3 c= -20 c=13
Δ=b²-4ac Δ=b²-4ac Δ=b²-4ac
Δ=(-4)²-4*1*3 Δ=1²-4*1*(-20) Δ=(-2)²-4*(-15)*13
Δ=16-4*3 Δ=1-4(-20) Δ=4+60*13
Δ=16-12 Δ=1+80 Δ=4+780
Δ=4 Δ=81 Δ=784
x= -b+-√Δ/2a x= -b+-√Δ/2a x= -b+-√Δ/2a
x= -(-4)+-√4/2*1 x= -1+-√81/2*1 x= -(-2)+-√784/(-15)
x=4+-2/2 x= -1+-9/2 x=2+-28/(-15)
x'=4+2/2 x'= -1+9/2 x'=2+28/(-15)
x'=6/2 x'=8/2 x'=30/(-15)
x'=3 x'=4 x'= -2
x''=4-2/2 x''= -1-9/2 x''=2-28/(-15)
x"=2/2 x''= -10/2 x''= -26/(-15)
x"=1 x"= -5 x''= -26/(-15)
D)4x²-2x²+7x-2x+3=0 E)x²-2x=2x+12
2x²+5x+3=0 x²-2x-2x-12=0
x²-4x-12=0
a=2
b=5
c=3 a=1 b= -4 c=-12
Δ=b²-4ac Δ=b²-4ac
Δ=5²-4*2*3 Δ=(-4)²-4*1*(-12)
Δ=25-24 Δ=16+48
Δ=1 Δ=64
x= -b+-√Δ/2a x= -b+-√Δ/2a
x= -5+-√1/2*2 x= -(-4)+-√64/2*1
x= -5+-1/4 x=4+-8/2
x'= -5+1/4 x'=4+8/2
x'= -4/4 x'=12/2
x'= -1 x'=6
x''= -5-1/4 x''=4-8/2
x''= -6/4 (simplificando por 2) x''= -4/2
x''= -3/2 x''= -2
F)2x²-x+6=4x+4 G)x²-2x-x+2=6
2x²-x-4x+6-4=0 x²-3x+2-6=0
2x²-5x+2=0 x²-3x-4=0
a=2 b= -5 c=2 a=1 b= -3 c= -4
Δ=b²=4ac Δ=b²-4ac
Δ=(-5)²-4*2*2 Δ=(-3)²-4*1*(-4)
Δ=25-16 Δ=9+16
Δ=9 Δ=25
x= -b+-√Δ/2a x= -b+-√Δ/2a
x= -(-5)+-√9/2*2 x= -(-3)+-√25/2*1
x=5+-3/4 x=3+-5/2
x'=5+3/4 x'=3+5/2
x'=8/4 x'=8/2
x'=2 x'=4
x"=5-3/4 x''=3-5/2
x''=2/4 (simplificando por 2) x''=2/2
x''=1/2 x''=1
H)2x²-16x-3x+24=34
2x²+19x+24-34=0
2x²+19x-10=0
a=2 b=19 c= -10
Δ=b²-4ac
Δ=19²-4*2*(-10)
Δ=361-8*(-10)
Δ=361+80
Δ=441
x= -b+-√Δ/2a
x= -19+-√441/2*2
x= -19+-21/4
x'= -19+21/4
x'= 2/4 (simplificando por 2)
x'= 1/2
x''= -19-21/4
x''= -40/4
x''= -10