Matemática, perguntado por joaovitordasilpcv213, 5 meses atrás

Me ajudem pfv, é pra entregar amanhã

Anexos:

Soluções para a tarefa

Respondido por Darquiley
0

Resposta:

Matriz C= \begin{gathered}\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\end{gathered}

[

0

−1

1

0

]

Explicação passo-a-passo:

A=\begin{gathered}\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\end{gathered}

[

a11

a21

a12

a22

]

B=\begin{gathered}\left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\end{gathered}

[

b11

b21

b12

b22

]

a11= 3×1 + 4×1 = 3 + 4 = 7

a12= 3×1 + 4×2 = 3 + 8 = 11

a21= 3×2 + 4×1 = 6 + 4 = 10

a22= 3×2 + 4×2 = 6 + 8 = 14

b11= (-4)×1 - 3×1 = (-4) - 3 = -7

b12= (-4)×1 - 3×2 = (-4) - 6 = -10

b21= (-4)×2 - 3×1 = (-8) - 3 = -11

b22= (-4)×2 - 3×2 = (-8) - 6 = -14

A=\begin{gathered}\left[\begin{array}{ccc}7&11\\10&14\end{array}\right]\end{gathered}

[

7

10

11

14

]

B=\begin{gathered}\left[\begin{array}{ccc}-7&-10\\-11&-14\end{array}\right]\end{gathered}

[

−7

−11

−10

−14

]

C=A+B

C=\begin{gathered}\left[\begin{array}{ccc}7&11\\10&14\end{array}\right]\end{gathered}

[

7

10

11

14

]

+ \begin{gathered}\left[\begin{array}{ccc}-7&-10\\-11&-14\end{array}\right]\end{gathered}

[

−7

−11

−10

−14

]

C=\begin{gathered}\left[\begin{array}{ccc}7+(-7)&11+(-10)\\10+(-11)&14(-14)\end{array}\right]\end{gathered}

[

7+(−7)

10+(−11)

11+(−10)

14(−14)

]

C=\begin{gathered}\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\end{gathered}

[

0

−1

1

0

]

Perguntas interessantes