Matemática, perguntado por 2000ALUNO2000, 1 ano atrás

Me ajudem pfv

a)9^x+1=³√3

b)0,8^x=(5/4)

c)0,2^x+1=√125

d)0,25^x+4=0,5^-2x+1

e)(³√125)x=(1/125)^-x+3

Soluções para a tarefa

Respondido por Usuário anônimo
2
a)9^x+1=³√3 

3^(2x+1)=3^(1/3)

2x+1=1/3

2x=-2/3
x=-1/3
############################

b)0,8^x=(5/4) 
(4/5)^x=(5/4)
(5/4)^(-x)=4/4

-x=1
x=-1 é a resposta

c)0,2^x+1=√125

(1/5)^(x+1)= 5^(3/3)

5^(-x-1)=5¹

-x-1=1

x=-2
##############################

d)0,25^x+4=0,5^-2x+1

(1/4) ^( x+4)=(1/2)^(-2x+1)
(1/2)^(2x+8)=(1/2)^(-2x+1)
2x+8=-2x+1
4x=-7
x=-7/4
#########################

e)(³√125)^x=(1/125)^-x+3

5^x =(5
⁻³)^(-x+3)

x=3x-9

2x=9

x=9/2
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