Question

Me ajudem pfv
???????​

Answer 1

Boa tarde!

㏒16 √128

= ㏒16 $128^{1/2}$

= $\frac{1}{2} . log_{16} 128$

= $\frac{log_{16} 128}{2}$

$log_{16} 128 = x\\16^{x} = 128\\(2^{4} )^{x} = 2^{7}\\2^{4x} = 2^{7}\\4x = 7\\x = \frac{7}{4}$

$\frac{log_{16}128 }{2} = \frac{\frac{7}{4} }{2} = \frac{7}{4} . \frac{1}{2}$

= $\frac{7}{8}$

Espero ter ajudado! Bons estudos