Question

Me ajudem pfv!!!!!!!!!!!!!!!!

Answer 1

Resposta:

1) Resova os produtos notáveis abaixo:

a)

$\Large\boxed{(a-b)^2=a^2-2ab+b^2}\\\\(3x - 5) {}^{2} = (3x) {}^{2} - 2(3x)(5) + {5}^{2} \\ \\ = \Large\boxed{ \green{9 {x}^{2} - 30x + 25}}$

b)

$(4a - b) {}^{2} = \\ \\ = (4a) {}^{2} - 2(4a)(b) + {b}^{2} \\ \\ = \Large \boxed{ \green{ 16 {a}^{2} - 8ab + {b}^{2} }}$

c)

$(y - 12) {}^{2} = \\ \\ = {y}^{2} - 2(y)(12) + {12}^{2} \\ \\ = \Large \boxed{ \green{ {y}^{2} - 24y + 144}}$

d)

$(5a - 6b) {}^{2} = \\ \\ = {(5a)}^{2} - 2(5a)(6b) + {(6b)}^{2} \\ \\ = \Large \boxed { \green{25 {a}^{2} - 60ab + 36 {b}^{2} }}$

e)

$( {x}^{2} - 3z) {}^{2} = \\ \\ = ( {x}^{2} ) {}^{2} - 2( {x}^{2} )(3z) + {(3 z)}^{2} \\ \\ = \Large \boxed{ \green{{x}^{4} - 6 {x }^{2} z + 9 {z}^{2} }} \\ \\ \Large \boxed{ \underline{ \blue{ \bf \: Bons \: Estudos!}11/05/2021}}$

Answer 2

a)

${(3x - 5)}^{2} = \\ {9x}^{2} - 30x + 25$

b)

${(4a - b)}^{2} = \\ {16a}^{2} - 8ab + {b}^{2}$

c)

${(y - 12)}^{2} = \\ {y}^{2} - 24y + 144$

d)

${(5a - 6b)}^{2} = \\ {25a}^{2} - 60ab + {36b}^{2}$

e)

[tex] {({x}^{2} - 3z)}^{2} = \\ {x}^{4} - {6x}^{2}z + {9z}^{2}