Question

Me ajudem pfv.....*****

Answer 1

Área =

at = área do triângulo

sen 60° = √3/2

$\dfrac{sen\ \alpha .\ a\ .\ b}{2} \\\\\\\\at= \dfrac{ \dfrac{ \sqrt{3} }{2} \times 4 \times 5}{2}\\\\\\at= \dfrac{ \sqrt{3} \times 2 \times 5}{2} \\\\\\at=5 \sqrt{3} \ cm^2$


Forte abraço!