Question

me ajudem pffffff!!!!!!!!!

Answer 1

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$\frac{2^{3+x}-2^{x-3}}{2^x+2^{x-3}} =$

desmembrar e colocar em evidência

$\frac{2^3.2^x-2^x.2^{-3}}{2^x+2^x.2^{-3}} = \\ \\ \frac{2^x(2^3-2^{-3})}{2^x(1+2^{-3})} = \\ \\ cancela~~2^x \\ \\ \frac{2^3-2^{-3}}{1+2^{-3}} = \\ \\ (8- \frac{1}{8} )\div(1+ \frac{1}{8} )= \\ \\ ( \frac{64-1}{8} )\div( \frac{8+1}{8} )= \\ \\ \frac{63}{8} \times \frac{8}{9} =7$

cancela 8 com 8
e 63 com 9