Question

Me ajudem pelo amor de Deus

Answer 1

Resposta:

$(\frac{1}{2}) ^{3x^{2}-2x } =1\\\\(\frac{1}{2}) ^{3x^{2}-2x } =(\frac{1}{2}) ^{0}\\\\3x^{2}-2x =0 \\x( 3x-2)=0 \\x1=0 \\x2= \frac{2}{3}$

Assim, x1+3x2= 0+6/3= 2