Matemática, perguntado por IsahNerd, 11 meses atrás

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Anexos:

Soluções para a tarefa

Respondido por 4288
1

A

3\left(-\frac{2}{3}\right)\\\\-3\cdot \frac{2}{3}\\\\-\frac{2\cdot \:3}{3}\\\\=-2

B

\frac{2}{3}\left(-\frac{3}{4}\right)\\\\-\frac{2}{3}\cdot \frac{3}{4}\\\\-\frac{2\cdot \:3}{3\cdot \:4}\\\\-\frac{2}{4}\\\\-\frac{1}{2}\\\\

C

\frac{\frac{8}{9}}{-\frac{4}{27}}\\\\-\frac{\frac{8}{9}}{\frac{4}{27}}\\\\-\frac{8\cdot \:27}{9\cdot \:4}\\\\-\frac{8\cdot \:27}{36}\\\\-\frac{216}{36}\\\\=-6

D

\frac{-\frac{12}{5}}{-\frac{6}{5}}\\\\\frac{\frac{12}{5}}{\frac{6}{5}}\\\\\frac{12\cdot \:5}{5\cdot \:6}\\\\\frac{12}{6}\\\\=2

E

\left(\frac{2}{5}\right)^2\left(-\frac{1}{4}\right)\\\\\left(-\frac{1}{4}\right)^3\frac{2^2}{5^2}\\\\\left(-\frac{1}{4^3}\right)\frac{2^2}{5^2}\\\\-\frac{2^2}{5^2}\cdot \frac{1}{4^3}\\\\-\frac{2^2\cdot \:1}{5^2\cdot \:4^3}\\\\-\frac{2^2}{4^3\cdot \:5^2}\\\\-\frac{1}{2^4\cdot \:5^2}\\\\=-\frac{1}{400}

F

\frac{\left(\frac{3}{4}\right)^2}{\left(\frac{1}{2}\right)^2}\\\\\left(\frac{\frac{3}{4}}{\frac{1}{2}}\right)^2\\\\\left(\frac{3}{2}\right)^2\\\\\frac{3^2}{2^2}\\\\=\frac{9}{4}

G

\left(-\frac{1}{4}\right)^2+\left(-\frac{1}{2}\right)^2\\\\\frac{1}{4^2}+\frac{1}{2^2}\\\\\frac{1}{16}+\frac{1}{2^2}\\\\\frac{1}{16}+\frac{1}{4}\\\\\frac{1}{16}+\frac{4}{16}\\\\\frac{1+4}{16}\\\\=\frac{5}{16}

H

\left(\frac{1}{3}\right)^2+\left(\frac{3}{2}\right)^2\\\\\frac{1}{3^2}+\frac{3^2}{2^2}\\\\\frac{1}{9}+\frac{3^2}{2^2}\\\\\frac{1}{9}+\frac{3^2}{4}\\\\\frac{4}{36}+\frac{81}{36}\\\\\frac{4+81}{36}\\\\=\frac{85}{36}

Espero ter ajudado.


IsahNerd: Muito obg!!
4288: Por nada.
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