Question

Me ajudem

Opção
A
B
C
D

Answer 1

Resposta:

Letra B.

Explicação passo-a-passo:

$\begin{center} \boxed{\sin{(\theta\pm\phi)}=\sin{\theta}\cos{\phi}\pm\sin{\phi}\cos{\theta}} \end{center}$

$\sin{\dfrac{5\pi}{3}}=\sin{\bigg(\dfrac{6\pi}{3}-\dfrac{\pi}{3}\bigg)}=\sin{\bigg(2\pi-\dfrac{\pi}{3}\bigg)}=\\\\ =\sin{2\pi}\cos{\dfrac{\pi}{3}}-\sin{\dfrac{\pi}{3}}\cos{2\pi}=0-\sin{\dfrac{\pi}{3}}(1)=\\\\ =\boxed{-\sin{\dfrac{\pi}{3}}}$