Question

ME AJUDEM

O resultado da expressão {1/3+[8²+4²]) ÷√256+2²}

Answer 1

Resposta:x2+2bx+b2−ba2−2ba−b=0

(1)⋅x2+(2b)⋅x+(b2−ba2−2ba−b)=0

x=−(2b)±(2b)2−4⋅(b2−ba2−2ba−b)−−−−−−−−−−−−−−−−−−−−−−−−√2

x=−2b±4b2−(4b2−4ba2−8ba−4b)−−−−−−−−−−−−−−−−−−−−−−−√2

x=−2b±4ba2+8ba+4b−−−−−−−−−−−−−√2

x=−2b±(2a+2)⋅b√2

x=(2)⋅[(−b)±(a+1)⋅b√](2)

x1=−b+(a+1)⋅b√

x2=−b−(a+1)⋅b√

n sei se esta certo