Question

Me ajudem o enunciado esta na foto

Answer 1

a)

$\frac{x - 4}{x - 1} = \frac{x - 5}{x - 1} \\ \\ \frac{x - 4}{x - 1} = \frac{x - 5}{x - 1} \: . \: x = 1.x = 3 \\ \\ (x - 4) \times (x - 3) = (x - 5) \times (x - 1) \\ \\ {x}^{2} - 3x - 4x + 12 = {x}^{2} - x - 5x + 5 \\ \\ - 3x - 4x + 12 = - x - 5x + 5 \\ \\ - 7x + 12 = - 6x + 5 \\ \\ - 7x + 6x = 5 - 12 \\ - x = - 7 \\ x = 7 \: .x = 1 \: .x = 3 \\ x = 7$

b)

$\frac{2x - 3}{x - 2} = \frac{x + 2}{2x + 3} \\ \\ \frac{2x - 3}{x - 2} = \frac{x + 2}{2x + 3}. \: x = 2 \: .x = \frac{3}{2} \\ (2x - 3) \times (2x - 3) = (x + 2) \times (x - 2) \\ (2x - 3) \times (2x - 3) - (x + 2) \times (x - 2) = 0 \\ (2x - 3 {)}^{2} - ( {x}^{2} - 4) = 0 \\ 4 {x}^{2} - 12x + 9 - {x}^{2} + 4 = 0 \\ 3 {x}^{2} - 12x + 13 = 0 \\ x = \frac{ - ( - 12) + \sqrt{( - 12 {)}^{2} - 4 \times 3 \times 13 } }{2 \times 3} \\ x = \frac{12 + \sqrt{ 114 - 156} }{6} \\ x = \frac{12 + \sqrt{ - 12} }{6}$

Solução "b"

x € R

Espero que ajude!