Question

me ajudem nisso pfvvvv

(Equação de 2 grau com uma incógnita)

*Foto*
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Answer 1

Resposta:

Explicação passo a passo:

1 - x² = 36                                    2 - x² = 49

x =$\sqrt{36}$                                         x = $\sqrt{49$

x = 6                                           x = 7

3 - x² = 900                               4 - x² = 400

x = $\sqrt{900}$                                     x = $\sqrt{400}$

x = 30                                         x = 20

5 - x² = 3600                             6 - x² = 169

x = $\sqrt{3600}$                                   x = $\sqrt{169}$

x = 60                                         x = 13

7 - 4y x² = 100                           8 - 81x² = 144

x = $\sqrt{100}$                                   x = $\sqrt{144}$

x = 10                                         x = 12

4y + 10 = 0                                81 * 12 = 972

4y = - 10

y = -10/4

y = -2,5

Answer 2

Resposta:

$1)~~~x^2=36\\ \\ x=\pm\sqrt{36} \\ \\ x=\pm6\\ \\ S=\{-6,6\}$

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$2)~~x^2=49\\ \\ x=\pm\sqrt{49} \\ \\ x=\pm7\\ \\ S=\{-7,7\}$

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$3)~~x^2=900\\ \\ x=\pm\sqrt{900} \\ \\ x=\pm\sqrt{9} .\sqrt{100} \\ \\ x=\pm30\\ \\ S=\{-30,30\}$

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$4)~~x^2=400\\ \\ x=\pm\sqrt{400} \\ \\ x=\pm\sqrt{4} .\sqrt{100} \\ \\ x=\pm20\\ \\ S=\{-20,20\}$

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$5)~~x^2=3600\\ \\ x=\pm\sqrt{3600} \\ \\ x=\pm\sqrt{36} .\sqrt{100} \\ \\ x=\pm60\\ \\ S=\{-60,60\}$

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$6)~~x^2=169\\ \\ x=\pm\sqrt{169} \\ \\ x=\pm13\\ \\ S=\{-13,13\}$

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$7)~~49x^2=100\\ \\ x^2=\dfrac{100}{49}\\\\ \\ x=\pm\sqrt{\dfrac{100}{49}} \\ \\ \\ x=\pm\dfrac{10}{7}\\ \\ \\ S=\{-\dfrac{10}{7},\dfrac{10}{7}\}$

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$8)~~81x^2=144\\ \\ \\ x^2=\dfrac{144}{81}\\ \\ \\ x=\pm\sqrt{\dfrac{144}{81}} \\ \\ \\ x=\pm\dfrac{12}{9}$

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$9)~~~121x^2=81\\ \\ \\ x^2=\dfrac{81}{121}\\ \\ \\ x=\pm\sqrt{\dfrac{81}{121}} \\ \\ \\ x=\pm\dfrac{9}{11}\\ \\ \\ S=\{-\dfrac{9}{11},\dfrac{9}{11}\}$