Question

Me ajudem nessas questões: 8^ײ-¹=4^×-1
5^×/5^ײ=1

Answer 1

A)

8^ײ-¹=4^×-1

2^3(x^2 - 1) = 2^2(x-1)
3.(x^2 - 1)= 2.(x-1)
3x^2 - 3 = 2x - 2
3x^2 - 2x - 3 + 2 = 0
3x^2 - 2x - 1 = 0
a = 3; b = - 2; c = - 1
/\= b^2 - 4ac
/\= (-2)^2 - 4.3.(-1)
/\= 4 + 12
/\= 16

x = (- b +/- \/ /\)/ 2a
X = [-(-2) +/- \/16] / 2.3
X = (2 +/- 4)/6
X' = (2+4)/6= 6/6= 1
x" = (2-4)/6= -2/6 (:2)/(:2)= - 1/3

R.:
S = {1, -1/3}
___________
B)

5^×/5^ײ=1
5^(x - x^2) = 5^0
x - x^2 = 0 (-1)
x^2 - x = 0
x.(x - 1)= 0
x' = 0
x - 1 = 0
x " = 1

R.:
S = {0,1}