Question

Me ajudem nessas duas questões pfvr!

Answer 1

$\frac{x}{x+2} = \frac{9}{12} \\ \\ 12x = 9(x+2) \\ \\ 12x = 9x+18 \\ \\ 12x - 9x = 18 \\ \\ 3x = 18 \\ \\ x = 6$



$\frac{x+5}{x} = \frac{x+2}{x-2} \\ \\ (x+5)(x-2)= x(x+2) \\ \\ x^2 -2x+5x-10=x^2+2x \\ \\ x^2-x^2-2x-2x+5x = 10 \\ \\ x = 10$