Question

Me Ajudem Nessas Contas!!!

Quero muito saber quais são as respostas!

matemática e suas expressões!!!
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Answer 1

Resposta:

a)

$(3x+1)*(x-1)-3(x+2)^{2} =-9\\3x^{2} -3x+x-1-3(x^{2} +4x+4)=-9\\3x^{2} -2x-1-3x^{2} -12x-12+9=0\\-14x-4=0\\(-14x=4)-1\\14x=-4\\x=-4/14\\x=-\frac{2}{7}$

b)

$\frac{x}{2} +\frac{4x-1}{3}=\frac{x-1}{2} \\\\\frac{3x+8x-2=3x-3}{6} \\\\3x+8x-2=3x-3\\\\8x=5\\\\x=\frac{5}{8}$

c)

$(x+1)^{2} =(3x+2)^{2} -(2x+3)^{2} \\x^{2}+2x+1=5x^{2} -5\\-4x^{2} +2x +6$

bhaskara

$\frac{2+-\sqrt{4+96} }{-8}$

Soma

$\frac{-2+10}{-8} =-1$

Subtração

$\frac{-2-10}{-8} =\frac{3}{2}$

x=(-1, 3/2)