Question

me ajudem nessa equação de 2 grau com bhaskara 2x^2-4x-1=0​

Answer 1

Resposta:

$2x {}^{2} - 4x - 1 = 0$

Coeficientes...

$a = 2 \\ b = - 4 \\ c = - 1$

Delta...

$d = b {}^{2} - 4ac$

$d = ( - 4) {}^{2} - 4 \times 2 \times ( - 1)$

$d = 16 + 8$

$d = 24$

Bhaskara...

$x = \frac{ - b +/- \sqrt{d} }{2a}$

$x = \frac{ - ( - 4) +/- \sqrt{24} }{2.2}$

$x = \frac{4 +/- \sqrt{24} }{4}$

$x = \frac{4 +/- 2 \sqrt{6} }{4}$

$x1 = \frac{4 + 2 \sqrt{6} }{4} = \frac{2(2 + \sqrt{6} )}{4} = \frac{ 2 + \sqrt{6} }{2} \\ x2 = \frac{4 - 2 \sqrt{6} }{4} = \frac{2(2 - \sqrt{6}) }{4} = \frac{2 - \sqrt{6} }{2}$

Espero ter ajudado!!!

Answer 2

∆ = b² – 4ac

∆ = (-4)² – 4 • 2 • (-1)

∆ = 16 + 8

∆ = 24

x₍₁,₂₎ = (–b ± √∆) / 2a

x₍₁,₂₎ = ( –(-4) ± √24) / 2•2

x₍₁,₂₎ = (4 ± 2√6)/4

x₍₁,₂₎ = 4 / 4 ± (2√6)/4

x₍₁,₂₎ = 1 ± (√6)/2
___________
x₁ = (2 + √6)/2

e

x₂ = (2 – √6)/2

Espero ter colaborado!)