Question

ME AJUDEM! Na função f: R->R, com f(x)=x²-2x+10 , determine:
a) f (-1/3) b )f (-5)

Answer 1

f(-1/3) = (-1/3)² - 2((1/3) + 10

f(1/3) = 1/9 -2/3 + 10

f(1/3) =( 3-18+10)/27 = -5/7

f(1/3) = -5/7

f (-5) = (-5)² -2(-5) +10

f(-5) = 25 +10 +10 = 45

f(-5) = 45