Question

Me ajudem na 2 Por favor

Answer 1

a) {11^3•(11^4)^2•11^-2}÷11^6={11^3•11^8•11^-2}÷11^6={11^3•11^6}÷11^6=11^9÷11^6=11^3

b){(2^4)^3•2^2•2^4}÷(2^11)^2={2^12•2^6}÷2^22=2^18÷2^22=2^-4

c)(10^-2•1/10^-3)÷0,01^-1= (10^-2•10^3)÷0,01^-1=
10^1÷10^-3=10^-2

d){10•10^-1•(10^2)^-3}÷(10^-4)^3=
{1•(10^2)^-3}÷10^-12=10^-6÷10^-12=10^6

Answer 2

a) [ (11^3)[(11^4)^2](11^-2) ]/(11^6)

[ (11^3)(11^4*2)(11^-2) ]/(11^6)
[(11^3)(11^8)(11^-2)]/(11^6)
(11^3+8-2)/(11^6)
(11^9)/(11^6)
(11^9-6)
11^3

resposta a): 11^3

b) { [(2^4)^3](2^2)(2^4)}/ (2^11)^2
[(2^12)(2^2)(2^4)]/(2^22)
( 2^12+2+4)/(2^22)
(2^18)/(2^22)
2^18-22
2^-4

resposta b) 2^-4

c) [(10^-2)][(1/10)^-3]/(0,01^-1)

explicando alguns detalhes: eu posso inverter (1/10)^-3 para 10^3 e 0,01^-1 é a mesma coisa que 1/100^-1 sendo que eu posso invertelo para 100^1. Resolvendo...

[(10^-2)(10^3)]/(100^1)
(10^-2+3)/(100^1)
(10^1)/(100^1)
10/100
simplificando por meionda divisão por 10, vem:
1/10
resposta c) 1/10


d) [(10*10^-1)((10^2)^-3)]/(10^-4)^3
[10(1/10)(10^-6)]/(10^-12)
[(10/10)(1/10^6)]/(1/10^12)
(1)(1/10^6)/(1/10^12)
(1/10^6)/(1/10^12)
10^12/10^6
10^12-6
10^6

resposta d): 10^6