Question

me ajudem-me
3x+7y=36 e x+7y=36​

Answer 1

$\LARGE\displaystyle{}\begin{cases}3x + 7y = 36 \\ \\ x + 7y = 36\end{cases} \\\\ \LARGE\displaystyle{}\begin{cases}3x + 7y = 36 \\ \\ 7y = 36 - x\end{cases} \\\\ \LARGE\displaystyle{}3x + 36 - x = 36 \\\\ \LARGE\displaystyle{}x = 0 \\\\ \LARGE\displaystyle{}7y = 36 - 0 \\\\ \LARGE\displaystyle{}y = \dfrac{36}{7} \\\\ \LARGE\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{\left(x,y\right) =\left(0, \dfrac{36}{7} \right) }}}\end{gathered} }$

$\LARGE\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{{ \red{Bons}} \blue{\:Estudos}}}}\end{gathered} }$

Answer 2

Resposta:

(0, 36/7).

Explicação passo a passo:

3x + 7y = 36

x + 7y = 36  ⇒ x = 36 - 7y

Substituindo x:

3(36 - 7y) + 7y = 36

108 - 21y + 7y = 36

- 14y = 36 - 108

- 14y = - 72  .(-1)

14y = 72

y = 72/14

y = 36/7.

x = 36 - 7y

x = 36 - 7 . 36/7

x = 36 - 252/7

x = 36 - 36

x = 0.