Question

Me ajudem e por favor
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Answer 1

Resposta:

Explicação passo-a-passo:

(Fatores primos: 2, 3, 5, 7...)

Propriedade: $\sqrt[n]{x^{m} }$= $x^{m/n}$

a) $\sqrt[10]{32}$ = $\sqrt[10]{2^{5} }$ = $2^{5/10}$ = $2^{1/2}$ = $\sqrt{2}$

b) $\sqrt[9]{27}$ = $\sqrt[9]{3^{3} }$ = $3^{3/9}$ =  $3^{1/3}$ = $\sqrt[3]{3}$

c) $\sqrt[16]{81}$ = $\sqrt[16]{3^{4} }$ = $3^{4/16}$ = $3^{1/4}$ =  $\sqrt[4]{3}$

d)  $\sqrt[6]{16}$ = $\sqrt[6]{2^{4} }$ = $\sqrt[3]{2^{2} }$

e) $\sqrt[8]{64}$ = $\sqrt[8]{2^{6} }$ = $2^{\frac{6}{8} }$ =  $2^{\frac{3}{4} }$ = $\sqrt[4]{2^{3} }$

f) $\sqrt[12]{1024}$ = $\sqrt[12]{ 2^{10}}$ = $2^{10/12}$ = $2^{5/6}$ = $\sqrt[6]{2^{5} }$