Question

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Answer 1

$senC= \frac{c.o}{h} = \frac{5}{13} \\ \\ cos~c= \frac{c.a}{h} = \frac{12}{13} \\ \\ tg~c =\frac{c.o}{c.a} = \frac{5}{12}$

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$sen~b= \frac{c.o}{h} = \frac{12}{13} \\ \\ cos~b= \frac{c.a}{h} = \frac{5}{13} \\ \\ tg~c= \frac{c.o}{ c.a} = \frac{12}{5}$

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b)
$sen~p= \frac{c.o}{h} = \frac{8}{17} \\ \\ con~p= \frac{c.a}{h} = \frac{15}{17} \\ \\ tg~p= \frac{c.o}{c.a} = \frac{8}{15}$
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$sen~q= \frac{15}{17} \\ \\ cos~q= \frac{8}{17} \\ \\ tg~q= \frac{15}{8}$

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2)
a)
$cos~60= \frac{c.a}{h} \\ \\ \frac{1}{2} = \frac{6}{x} \\ \\ x=12$
b)
$tg~30= \frac{c.o}{c.a} \\ \\ \frac{ \sqrt{3} }{3} = \frac{4 \sqrt{3} }{x} \\ \\ x \sqrt{3} =12 \sqrt{3} \\ \\ x=12$


c)
$tg~45= \frac{c.o}{c.a} \\ \\ 1= \frac{15}{ \frac{x}{2} } \\ \\ \frac{x}{2} =15 \\ \\ x=30$