me ajudem com teorema de tales
Anexos:
![](https://pt-static.z-dn.net/files/d24/5bc2e2d438e1747e1d41da8a3ed1adaa.jpg)
Soluções para a tarefa
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Aplicando Tales:
![\frac{x+9+y+5}{9} = \frac{D+2x+3x-2}{2x} \\ \\ 2x(x+9+y+5)=9(D+2x+3x-2) \\ \\ \frac{x+9+y+5}{x} = \frac{D+2x+3x-2}{D} \\ \\ D(x+9+y+5)=x(D+2x+3x-2) \\ 2x(x+9+y+5)=9(D+2x+3x-2) \\ \\ x=9 \\ D=2x==\ \textgreater \ D=18 \\ \\ \frac{y+23}{9} = \frac{61}{18} \\ \\ 549=18y+414 \\ \\ 18y=135==\ \textgreater \ y=7,5 \frac{x+9+y+5}{9} = \frac{D+2x+3x-2}{2x} \\ \\ 2x(x+9+y+5)=9(D+2x+3x-2) \\ \\ \frac{x+9+y+5}{x} = \frac{D+2x+3x-2}{D} \\ \\ D(x+9+y+5)=x(D+2x+3x-2) \\ 2x(x+9+y+5)=9(D+2x+3x-2) \\ \\ x=9 \\ D=2x==\ \textgreater \ D=18 \\ \\ \frac{y+23}{9} = \frac{61}{18} \\ \\ 549=18y+414 \\ \\ 18y=135==\ \textgreater \ y=7,5](https://tex.z-dn.net/?f=+%5Cfrac%7Bx%2B9%2By%2B5%7D%7B9%7D+%3D+%5Cfrac%7BD%2B2x%2B3x-2%7D%7B2x%7D++%5C%5C++%5C%5C+2x%28x%2B9%2By%2B5%29%3D9%28D%2B2x%2B3x-2%29+%5C%5C++%5C%5C++%5Cfrac%7Bx%2B9%2By%2B5%7D%7Bx%7D+%3D+%5Cfrac%7BD%2B2x%2B3x-2%7D%7BD%7D++%5C%5C++%5C%5C+D%28x%2B9%2By%2B5%29%3Dx%28D%2B2x%2B3x-2%29+%5C%5C++2x%28x%2B9%2By%2B5%29%3D9%28D%2B2x%2B3x-2%29+%5C%5C+%5C%5C+x%3D9+%5C%5C+D%3D2x%3D%3D%5C+%5Ctextgreater+%5C+D%3D18+%5C%5C++%5C%5C++%5Cfrac%7By%2B23%7D%7B9%7D+%3D+%5Cfrac%7B61%7D%7B18%7D++%5C%5C++%5C%5C+549%3D18y%2B414+%5C%5C++%5C%5C+18y%3D135%3D%3D%5C+%5Ctextgreater+%5C+y%3D7%2C5)
Solução: x= 9
D= 18
y= 7,5
Solução: x= 9
D= 18
y= 7,5
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