Question

Me ajudem com esses calculos, qual é o resultado?

Answer 1

veja

$\frac{3x}{8} - \frac{5}{6} = \frac{x}{3} - \frac{5}{2}$

mmc(8,6,3,2)=24

$\frac{9x-20=8x-60}{24} \\ 9x-8x=-60+20 \\ x=-40$

b)

$\frac{2y}{5} -4= \frac{y}{4} +2$

mmc(5,4)=20

$\frac{8y-80=5y+40}{20} \\ 8y-5y=40+80 \\ 3y=120 \\ y=120\div3 \\ y=40$

c)
$x-4- \frac{x+4}{3} =0$

mmc=3

$\frac{3x-12-1(x+4)}{3} =0 \\ 3x-12-x-4=0 \\ 2x=+12+4 \\ 2x=16 \\ x=16\div2 \\ x=8$

Answer 2

E) 9x/24-20/24=8x/24-60/24
9x-8x=-60+20
X=-40


F)8y/20-80/20=5y/20+40/20
8y-5y=40+80
3y=120
Y=40


G)3x/3-12/3-3x/3+12/3=0
3x-12-3x-12=0
-24