Question

Me ajudem com esse aqui por favor

Answer 1

Resposta:

$W=tg(x)$

Explicação passo a passo:

$W=\frac{sen(x+y)+sen(x-y)}{cos(x+y)+cos(x-y)} \\\\\\W=\frac{sen(x)cos(y)+sen(y)cos(x)+sen(x)cos(y)-sen(y)cos(x)}{cos(x)cos(y)-sen(x)sen(y)+cos(x)cos(y)+sen(x)sen(y)}$

$W=\frac{2[sen(x)cos(y)]}{2[cos(x)cos(y)]} \\\\\\W=\frac{sen(x)cos(y)}{cos(x)cos(y)} \\\\\\W=\frac{sen(x)}{cos(x)}\\\\\\W=tg(x)$

Answer 2

Vamos là.

w = (sen(x + y) + sen(x - y))/(cos(x + y) + cos(x - y))

w = 2sen(x)*cos(y)/(2cos(x)*cos(y))

w = sen(x)/cos(x) = tg(x)