Question

me ajudem com essas equações pfvr :(

5(2x+1)-3(x+2)=5x+6

6(2+x)-3(x-1)=12+x-1

12-3(x+2)+42=5x-1

3(2+x)-x=6+x

Answer 1

5(2x+1)-3(x+2)=5x+6
10x+5-3x-6=5x+6
10x-3x-5x=6-5+6
2x=7÷2
x=3,5

6(2+x)-3(x-1)=12+x-1
12+6x-3x+3=12+x-1
6x-3x-x=12-1-12
2x=11-12
2x= -1÷2
x= -0,5

12-3(x+2)+42=5x-1
12-3x-6+42=5x-1
-3x-5x=-1-12+6-42
-8x=-13+6-42
-8x= -7-42
-8x= -49 .(-1)
8x= 49÷8
x=6,125

3(2+x)-x=6+x
6+3x-x=6+x
3x-x-x=6-6
x=0

Answer 2

5 (2x+1) -3 (x+2) = 5x + 6
10x + 5 - 3x - 6 = 5x + 6
10x - 3x - 5x = 6 - 5 + 6
10x - 8x = 1 + 6
2x = 7
x = 7/2
x = 3,5

6 (2+x) -3 (x-1) = 12 + x - 1
12 + 6x - 3x + 3 = 12 + x - 1
6x - 3x - x = 12 - 1 - 3 - 12
6x - 4x = 12 - 16
2x = - 4
x = -4/2
x = -2

12 -3 (x+2) + 42 = 5x - 1
12 - 3x - 6 + 42 = 5x - 1
12 - 6 + 42 + 1 = 5x + 3x
6 + 42 + 1 = 5x + 3
49 = 8x
x = 49/8
ou x = 6,125

3 (2+x) - x = 6 + x
6 + 3x - x = 6 + x
3x - x - x = 6 - 6
3x - 2x = 0
x = 0

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