Question

Me ajudem com essa questão em anexo

Answer 1

$an = \frac{ {n}^{2} }{2n + 1} \\ \binom{b1 = 0}{bp + 1 = 1 - bp}$

$C 1 = \frac{ {1}^{2} }{2 \times 1 + 1 } + 0 = \frac{1}{3}$

$C 2 = \frac{ {2}^{2} }{2 \times 2 + 1} + (1 - 0) = \frac{4}{5} + 1 = \frac{9}{5}$

$C 3 = \frac{ {3}^{2} }{2 \times 3 + 1} + 0 = \frac{9}{7}$

$C 4 = \frac{ {4}^{2} }{2 \times 4 + 1} + 1 = \frac{16}{9} + 1 = \frac{25}{9}$