Question

Me ajudem ai pfvr,e se puderem fazer as explicações façam pfvr

Answer 1

Resposta:

$( \frac{3}{5} ) {}^{2} = \frac{3 {}^{2} }{5 {}^{2} } = \boxed{ \frac{9}{25} }$

$( \frac{4}{7} ) {}^{5} = \frac{4 {}^{5} }{7 {}^{5} } = \boxed{ \frac{1.024}{16.807} }$

$( \frac{2}{9} ) {}^{2} = \frac{2 {}^{2} }{9 {}^{2} } = \boxed{ \frac{4}{81} }$

$( \frac{5}{2} ) {}^{5} = \frac{5 {}^{5} }{2 {}^{5} } = \boxed{ \frac{3.125}{32} }$

$( \frac{6}{5} ) {}^{2} = \frac{6 {}^{2} }{5 {}^{2} } = \boxed{ \frac{36}{25} }$

$( \frac{1}{10} ) {}^{4} = \frac{1 {}^{4} }{10 {}^{4} } = \boxed{ \frac{1}{10.000} }$

$( \frac{4}{5} ) {}^{ - 2} = ( \frac{5}{4} ) {}^{2} = \frac{5 {}^{2} }{4 {}^{2} } = \boxed{ \frac{25}{16} }$

$( \frac{2}{3} ) {}^{ - 3} = ( \frac{3}{2} ) {}^{3} = \frac{3 {}^{3} }{2 {}^{3} } = \boxed{ \frac{27}{8} }$

$( \frac{1}{3} ) {}^{ - 2} = ( \frac{3}{1} ) {}^{2} = \frac{3 {}^{2} }{1 {}^{2} } = \boxed{ \frac{9}{1} }$

$( \frac{3}{5} ) {}^{ - 3} = ( \frac{5}{3} ) {}^{3} = \frac{5 {}^{3} }{3 {}^{3} } = \boxed{ \frac{125}{27} }$

$( \frac{10}{3} ) {}^{ - 4} = ( \frac{3}{10} ) {}^{4} = \frac{3 {}^{4} }{10 {}^{4} } = \boxed{ \frac{81}{10.000} }$

espero ter ajudado!!!!!