Question

me ajudem ai galera
a)
$9 \times ({ \frac{1}{4}) }^{2x - 3} = 4$
b)
${5}^{3x - 1} = { \frac{1}{25} }^{2x + 3}$

​

Answer 1

Resposta:

$b)\\ 5^{3x-1}={({1\over25})^{2x+3}$

$5^{3x-1}=(5^{-2})^{2x+3}\\ \\ 5^{3x-1}=5^{-4x-6}\\ \\ cancela~~5\\ \\ 3x-1=-4x-6\\ \\ 3x+4x=-6+1\\ \\ 7x=-5\\ \\ x=-{5\over7}\\ \\ S=\{-{5\over7}\}$