Question

me ajudem a responder ?x²-9x+20=0 Qual é a resposta

Answer 1

$x^2-9x+20=0$

Coeficientes: a = 1, b = -9 e c = 20

$\Delta=b^2-4ac\\\Delta=(-9)^2-4\cdot1\cdot20\\\Delta=81-80\\\Delta=1$

$x=\frac{-b+-\sqrt{\Delta}}{2a}\\\\x=\frac{-(-9)+-\sqrt{1}}{2\cdot1}\\\\x=\frac{9+-1}{2}\\\\x_1=\frac{9+1}{2}=\frac{10}{2}=5\\\\x_2=\frac{9-1}{2}=\frac{8}{2}=4$



Espero ter ajudado.
Bons estudos! :)