Question

Me ajudem a responder todas elas.
a) 4(x - 2) = 4+2(x - 1)
R:
b) 5[-x + 2(x+4)] = 2(3x + 19)
R:
c) 1/6+x/2=2x/3+1/4
R:
2m-5/8+m-1/2=13m+3/4
R:
4x+1/3+2(x+1)/3=5(3x+2)/4
R:

Answer 1

Explicação passo-a-passo:

$a) \: 4(x - 2) = 4 + 2(x - 1) \\ 4x - 8 = 4 + 2x - 2 \\ 4x - 2x = 4 - 2 + 8 \\ 2x = 10 \\ x = \frac{10}{2} \\ \\ x = 5$

$b) \: 5 | - x + 2(x + 4)| = 2(3x + 19) \\ 5| - x + 2x + 8| = 6x + 38 \\ - 5x + 10x + 40 = 6x + 38 \\ - 5x + 10x - 6x = 38 - 40 \\ - x = - 2 \\ x = 2$

$\frac{1}{6} + \frac{x}{2} = \frac{2x}{3} + \frac{1}{4} \\ \\ \frac{2x}{3} - \frac{x}{2} = \frac{1}{4} - \frac{1}{6} \\ \\ \frac{4x - 3x}{6} = \frac{3 - 2}{12} \\ \\ \frac{x}{6} = \frac{1}{12} \\ \\ 12x = 6 \\ x = \frac{6}{12} \\ \\ x = \frac{1}{2}$

$2m - \frac{5}{8} + m - \frac{1}{2} = 13m + \frac{3}{4} \\ \\ 13m - 2m - m = \frac{3}{4} + \frac{5}{8} + \frac{1}{2} \\ \\ 10m = \frac{6 + 5 + 4}{8} \\ \\ 10m = \frac{15}{8} \\ \\ m = \frac{ \frac{15}{8} }{10} \\ \\ m = \frac{15}{8} \times \frac{1}{10} \\ \\ m = \frac{15}{80} \\ \\ m = \frac{3}{16}$

$e) \: 4x + \frac{1}{3} + 2 \frac{x + 1}{3} = 5 \frac{3x + 2}{4} \\ \\ 4x + \frac{1}{3} + \frac{2x + 2}{3} = \frac{15x + 10}{4} \\ \\ 4x + \frac{2x + 2}{3} - \frac{15x + 10}{4} = - \frac{1}{3} \\ \\ \frac{48x + 8x + 8 - 45x + 30}{12} = - \frac{1}{3} \\ \\ \frac{11x + 38}{12} = - \frac{1}{3} \\ \\ - 33x - 114 = - 12 \\ - 33x = - 12 + 114 \\ x = - \frac{102}{33}$