Question

me ajudem a responder essa questão

2
 A + 3
---------- para: a= 1/2 m= -1/3
1 + m

Answer 1

Olá.


$\dfrac{2a+3}{1+m}$

$\dfrac{2\cdot(\dfrac{1}{3})+3}{1+(-\dfrac{1}{3})}=\dfrac{\dfrac{2}{3}+3}{1-\dfrac{1}{3}}=\dfrac{\dfrac{2+9}{3}}{\dfrac{3-1}{3}}=\dfrac{\dfrac{11}{3}}{\dfrac{2}{3}}=\dfrac{11}{3}\cdot\dfrac{3}{2}=(\dfrac{33}{6})^{:3}=\boxed{\dfrac{11}{2}=5,5}$


$\dfrac{a^2+3}{1+m}$
$<span>\dfrac{(\dfrac{1}{3^2})+3}{1+(-\dfrac{1}{3})}=\dfrac{\dfrac{1}{9}+3}{1-\dfrac{1}{3}}=$

$\dfrac{\dfrac{1+27}{9}}{\dfrac{3-1}{3}}=\dfrac{\dfrac{28}{9}}{\dfrac{2}{3}}=\dfrac{28}{9}\cdot\dfrac{3}{2}=(\dfrac{84}{18})^{:6}=\boxed{\dfrac{14}{3}=4,\overline6}$

Qualquer dúvida, deixe nos comentários.
Bons estudos.