Question

Me ajudem a resolver, por favor!!!
agradeço desde já! sz ​

Answer 1

Resposta:

$\tan(60) = \frac{12}{x} \\ \sqrt{3} = \frac{12}{x} \\ \sqrt{3}x = 12 \\ x = \frac{12}{ \sqrt{3} } . \frac{ \sqrt{3} }{ \sqrt{3} } \\ x = \frac{12 \sqrt{3} }{3} \\ x = 4 \sqrt{3}$

$\sin(30) = \frac{4 \sqrt{3} }{y} \\ \frac{1}{2} = \frac{4 \sqrt{3} }{y} \\ y = 8 \sqrt{3}$