Question

me ajudem a resolver por favo​

Answer 1

A) $2^2.4^4.8^-^2$ = (2*2) x (4*4*4*4) x ($\frac{1}{8^2}$) = 4 x 128 x 1/64 = 512/64 = 8

A = 8

B) $3^{2} . 27^{-1} . 9^{1}$ = (3*3) x (1/27) x 9 = 9 x 1/27 x 9 = 81/27 = 3

B = 3

C) $5^{3} . 25^{-1} . 625^{0}$ = (5*5*5) x (1/25) x 1 (todo numero elevado a 0 é 1) = 125/25 = 5

C = 5

D) $4^{3} . 27^{2} . 32^{-1} . 2^{1} . 9^{3}$ = (4*4*4) x (27*27) x 1/32 x 2 x (9*9*9) = 64 x 729 x 1/32 x 2 x 729 = 68024448/32 = 2125764

D = 2125764