Question

me ajudem a resolver isso pfv

[4²+(5-3)²]:(9-7)²

Answer 1

$\textsf{Para resolver essa conta devemos respeitar a ordem das opera\c c\~ oes:}\\\textsf{1. Parenteses, colchetes e chaves: ( ) [ ] ,{}} \mathsf{\left\{ \right\} }}\\\textsf{2. Expoentes e raizes: } \mathsf{4^2 \ \sqrt2}\\\textsf{3. Multiplica\c c\~oes e divis\~oes: } \mathsf{\times \ e \ :}\\\textsf{4. Somas e subtra\c c\~ oes: + e --}$

$\mathsf{[4^2 + (5 - 3)^2]:(9 - 7)^2 =}\\\mathsf{ [4^2 + 2^2] : 2^2 =}\\\mathsf{ [16 + 4] : 4 =}\\\mathsf{ 20 : 4 = }\\\mathsf{5}$

Answer 2

Oie, Td Bom?!

$= [4 {}^{2} + (5 - 3) {}^{2} ] \div (9 - 7) {}^{2}$

$= [4 {}^{2} + 2 {}^{2} ] \div 2{}^{2}$

$= [16 + 4] \div 4$

$= 20 \div 4$

$= 5$

Att. Makaveli1996