Question

Me ajudem a resolver essa questao??

Answer 1

$[ \frac{ (-\frac{3}{4}) ^{-2} +6. (\frac{ 3^{-1} }{4} ) -4}{7. (\frac{-3}{4}) ^{-1} +2} ]^-1$

$[ \frac{3. \frac{4^2}{3^2}+6. \frac{1}{3.4}-4 }{7. (-\frac{4}{3}+2 }]^{-1} = \\ \\ = [ \frac{3. \frac{4^2}{3^2}+6. \frac{1}{12}-4 }{7. (-\frac{4}{3}+2 }]^{-1} =$

$= [\frac{3. \frac{16}{9}+ \frac{1}{2} -4 }{ -\frac{28}{3}+2 }] ^{-1} =$

$= [\frac{\frac{16}{3}+ \frac{1}{2} -4 }{ \frac{-28+6}{3} }] ^{-1} = \\ \\ = [\frac{\frac{32+3-24}{6}}{ \frac{-28+6}{3} }] ^{-1} = \\ \\= [\frac{\frac{11}{6}}{ \frac{-22}{3} }] ^{-1} = [ \frac{11}{6}. \frac{3}{22} ] ^{-1} =$

$= [ -\frac{11}{44} ]^{-1} =- \frac{44}{11} =-4$