Question

me ajudem a resolver essa ;)

Answer 1

$\sqrt{x^2+y^2}\\ \\ \sqrt{6^2+4^2}= \sqrt{36+16}= \sqrt{52}=2 \sqrt{13}$

Answer 2

$\sqrt{x ^{2} + {y} ^{2} }= \sqrt{6 ^{2}+4 ^{2} }= \sqrt{36+16}= \sqrt{52}= 2\sqrt{13}$